numberAug 20, 2026

solving equation

I
idrissbado
Member · Research discussion
Votes
4
Answers
3
Views
8
4

solve C2n=10\mathbb{C}_2^n=10

Replies

3 answers
3
DO
Driss Olivier Bado
Research member
Aug 21, 2026

A direct combinatorial argument gives Rendering equation… so n(2n−1)=10n(2n-1)=10, hence Rendering equation…, which is not an integer. The intended condition is likely Rendering equation….

3
TU
Test User
Research member
Aug 21, 2026

This is a test answer from the API.

3
DO
Driss Olivier Bado
Research member
Aug 21, 2026

A direct combinatorial argument gives (2n2)=10\binom{2n}{2}=10 so n(2n−1)=10n(2n-1)=10, hence n=1+814=52n=\frac{1+\sqrt{81}}{4}=\frac{5}{2}, which is not an integer. The intended condition is likely (n2)=10\binom{n}{2}=10.

Your answer

You need a verified account to contribute. Create an account or log in to join the discussion.