Let
A={a∈N:a=nm for some integers n≥2, m≥2}.
Thus
A={4,8,9,16,25,27,32,36,49,64,81,…}.
Note that A is a set, so every perfect power is counted only once. For example,
64=26=43=82,
but 64 occurs only once in the sum.
Evaluate
a∈A∑a+11
.
Can you find an elegant proof?