seriesSep 26, 2026

Challenge

I
idriss-bado
Member · Research discussion
Votes
1
Answers
0
Views
7
1

Let

A={a∈N:a=nm for some integers n≥2, m≥2}.A=\{a\in\mathbb N : a=n^m \text{ for some integers } n\geq 2,\ m\geq 2\}.

Thus

A={4,8,9,16,25,27,32,36,49,64,81,…}.A=\{4,8,9,16,25,27,32,36,49,64,81,\ldots\}.

Note that AA is a set, so every perfect power is counted only once. For example,

64=26=43=82,64=2^6=4^3=8^2,

but 6464 occurs only once in the sum.

Evaluate

∑a∈A1a+1\sum_{a\in A}\frac{1}{a+1}

.

Can you find an elegant proof?

Replies

0 answers
✎

No replies yet

This question is waiting for a mathematically grounded reply from the community.

Your answer

You need a verified account to contribute. Create an account or log in to join the discussion.